3^(x-4)=(3^3)^x+28

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Solution for 3^(x-4)=(3^3)^x+28 equation: 



3^(x-4)=(3^3)^x+28

We move all terms to the left:

3^(x-4)-((3^3)^x+28)=0

We get rid of parentheses

3^(x-4)-3^3^x-28=0

We move all terms containing x to the left, all other terms to the right

3^(x-4)-3^3^x=28

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